x^2+9=(x+3)(x-3)

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Solution for x^2+9=(x+3)(x-3) equation: 



x^2+9=(x+3)(x-3)

We move all terms to the left:

x^2+9-((x+3)(x-3))=0

We use the square of the difference formula

x^2+x^2+9+9=0

We add all the numbers together, and all the variables

2x^2+18=0

a = 2; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·2·18
Δ = -144
Delta is less than zero, so there is no solution for the equation

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